Bluetooth Terminal

Разработчик: Lukas Pistrol

Описание

## Version 3 is now available ##
With Bluetooth LE Terminal you can easily prototype your Bluetooth Smart enabled hardware. Send individual bytes encoded as ASCII, HEX or Decimal numbers and receive data from your hardware accessory.
Test your data transfers even before having your own app!
# More Features:
• Send bytes as ASCII, HEX or Decimal
• See device's services and characteristics and their associated values
• Get information about your device such as name, UUID, and RSSI readings
• Setup a button matrix (game controller) to send different data with just a tap.
• Apple Watch support for button matrix
• Send the current time as a unix timestamp (seconds since 1970)
• Export current session as CSV
• Use the app in split-view or slide-over on iPad
If you have any questions about the app, or requests for features you would like to see, just write a short review or use the button inside the app to contact me!
* Some features may require an optional one-time in app purchase.
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Встроенные покупки

Controller Buttons
€3.99
Remove Ads
€3.99
Show RSSI Values
€0.99
Time Stamp
€0.99
Buy me 3 coffees
€9.99
Buy me 1 coffee
€1.99
Buy me 2 coffees
€4.99

Скриншоты

Bluetooth Terminal Частые Вопросы

  • Приложение Bluetooth Terminal бесплатное?

    Да, Bluetooth Terminal можно скачать бесплатно, однако в приложении есть встроенные покупки или подписки.

  • Является ли Bluetooth Terminal фейковым или мошенническим?

    ⚠️ Приложение Bluetooth Terminal имеет низкие оценки и отрицательные отзывы. Пользователи, похоже, недовольны его качеством или функциями.

    Спасибо за ваш голос

  • Сколько стоит Bluetooth Terminal?

    Bluetooth Terminal имеет несколько покупок/подписок внутри приложения, средняя цена покупки составляет €3.85.

  • Сколько зарабатывает Bluetooth Terminal?

    Чтобы получить оценку дохода приложения Bluetooth Terminal и другие данные AppStore, вы можете зарегистрироваться на платформе мобильной аналитики AppTail.

Оценки пользователей

5 из 5

1 оценок в Франция

5 star
1
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1 star
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История оценок

Bluetooth Terminal Отзывы Пользователей

button option it does not work and the apple watch does not work !!

Luccio38190 on

Франция

hellos I installed the app works. I installed the button option it does not work and the apple watch option also does not work !!

Attention l’option payante ne fonctionne pas

Remy222 on

Франция

Après avoir pris contact avec le développeur sans réponses je vous confirme que l’application payante ne fonctionne pas, dès que ont ouvre l’application le Bluetooth se déconnecte. Attention pas de remboursement possible de la part d’Apple store. Double arnaque!!!

Crash

Stephane@ on

Франция

Crash direct on refresh...

OK but...

téji on

Франция

Unable to receive ASCII characters :-(

Andrew Lee Cruz Malea Hood Cash Hood Clair Hood

Andrew OmegaT Cruz on

Соединенные Штаты

import torch from transformers import AutoTokenizer, AutoModelForSequenceClassification from hashlib import sha256 import os class KingsGuard: def __init__(self, password): self.password_hash = sha256(password.encode()).hexdigest() self.tokenizer = AutoTokenizer.from_pretrained("huggingface/llama") self.model = AutoModelForSequenceClassification.from_pretrained("huggingface/llama") def authenticate(self, attempt): return sha256(attempt.encode()).hexdigest() == self.password_hash def check_message(self, message): inputs = self.tokenizer(message, return_tensors="pt") outputs = self.model(**inputs) prediction = torch.argmax(outputs.logits, dim=1).item() return "Warning: Possible threat detected." if prediction == 1 else "Message is safe." class SecureTerminal: def __init__(self): self.authenticated = False self.guard = None def set_guard(self, password): self.guard = KingsGuard(password) def authenticate_user(self, attempt): if self.guard.authenticate(attempt): self.authenticated = True print("Authentication successful. Welcome!") else: print("Authentication failed. Access denied.") def execute_command(self, command): if self.authenticated: os.system(command) else: print("Please authenticate first.") def main(): terminal = SecureTerminal() password = input("Set your King's Guard password: ") terminal.set_guard(password) while True: attempt = input("Enter password to authenticate: ") terminal.authenticate_user(attempt) if terminal.authenticated: break while True: command = input("SecureTerminal#> ") if command.lower() == "exit": print("Exiting the terminal. Goodbye!") break if command.startswith("check "): message = command[6:] result = terminal.guard.check_message(message) print(result) else: terminal.execute_command(command) if __name__ == '__main__': main()

没中文

蘑菇街路口了 on

Соединенные Штаты

没中文,

Error

adama119 on

Соединенные Штаты

Dialog said“Reading is not permitted.” When I send any character to BLE decice.

Customizations and infographics

titopher8 on

Соединенные Штаты

Please allow for selection or deselection of data type listings.

can't connect to LEGO robot inventor hub

zencuke on

Соединенные Штаты

When the LEGO hub is bluetooth connected to a Macintosh or PC it is installed as a virtual serial device. I can then connect to it with standard terminal emulation software. However the bluetoothLE app on iOS just shows it as a device with no services. Not useful. Why can off the shelf OS software figure this out but this specialized bluetooth app cannot?

Meh

Debodawg on

Соединенные Штаты

Not all functions work Game controller doesn’t really send the correct text. Data that comes back on reads is normally decimal. Needs a decimal to ascii text decoder feature. Also needs a method to log read data to a file

Оценки

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Категория
Позиция
Топ бесплатных
9
Топ по доходу
11
Топ бесплатных
12
Топ бесплатных
12
Топ бесплатных
13

Ключевые слова

Bluetooth Terminal Конкуренты

Bluetooth Terminal Установки

30дн.

Bluetooth Terminal Доход

30дн.

Bluetooth Terminal Доходы и Загрузки

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Информация о приложении

Категория
Developer Tools
Разработчик
Lukas Pistrol
Языки
English
Последнее обновление
3.4.1 (1 год назад )
Выпущено
Nov 20, 2015 (9 лет назад )
Обновлено
4 дня назад
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